std::is_compound
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                    | Defined in header  <type_traits> | ||
| template< class T > struct is_compound; | (since C++11) | |
If T is a compound type (that is, array, function, object pointer, function pointer, member object pointer, member function pointer, reference, class, union, or enumeration, including any cv-qualified variants), provides the member constant value equal true. For any other type, value is false.
| Contents | 
[edit] Template parameters
| T | - | a type to check | 
[edit] Helper variable template
| template< class T > constexpr bool is_compound_v = is_compound<T>::value; | (since C++17) | |
Inherited from std::integral_constant
Member constants
| value [static] | true if Tis a compound type , false otherwise(public static member constant) | 
Member functions
| operator bool | converts the object to bool, returns value(public member function) | 
| operator() (C++14) | returns value(public member function) | 
Member types
| Type | Definition | 
| value_type | bool | 
| type | std::integral_constant<bool, value> | 
[edit] Notes
Compound types are the types that are constructed from fundamental types. Any C++ type is either fundamental or compound.
[edit] Possible implementation
| template< class T > struct is_compound : std::integral_constant<bool, !std::is_fundamental<T>::value> {}; | 
[edit] Example
Run this code
Output:
T is compound T is not a compound
[edit] See also
| (C++11) | checks if a type is fundamental type (class template) | 
| (C++11) | checks if a type is scalar type (class template) | 
| (C++11) | checks if a type is object type (class template) | 
| (C++11) | checks if a type is an array type (class template) | 
| (library fundamentals TS) | variable template alias of std::is_compound::value(variable template) | 


