std::literals::chrono_literals::operator""h
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                    | Defined in header  <chrono> | ||
| constexpr chrono::hours operator "" h(unsigned long long hrs); | (1) | (since C++14) | 
| constexpr chrono::duration</*unspecified*/, std::ratio<3600,1>> operator "" h(long double hrs); | (2) | (since C++14) | 
Forms a std::chrono::duration literal representing hours.
1) integer literal, returns exactly std::chrono::hours(hrs) 
2) floating-point literal, returns a floating-point duration equivalent to std::chrono::hours
| Contents | 
[edit] Parameters
| hrs | - | the number of hours | 
[edit] Return value
The std::chrono::duration literal.
[edit] Possible implementation
| constexpr std::chrono::hours operator ""h(unsigned long long h) { return std::chrono::hours(h); } constexpr std::chrono::duration<long double, ratio<3600,1>> operator ""h(long double h) { return std::chrono::duration<long double, std::ratio<3600,1>>(h); } | 
[edit] Notes
These operators are declared in the namespace std::literals::chrono_literals, where both literals and chrono_literals are inline namespaces. Access to these operators can be gained with using namespace std::literals, using namespace std::chrono_literals, and using namespace std::literals::chrono_literals.
In addition, within the namespace std::chrono, the directive using namespace literals::chrono_literals; is provided by the standard library, so that if a programmer uses using namespace std::chrono; to gain access to the duration classes, the duration literal operators become visible as well.
[edit] Example
Run this code
#include <iostream> #include <chrono> int main() { using namespace std::chrono_literals; auto day = 24h; auto halfhour = 0.5h; std::cout << "one day is " << day.count() << " hours\n" << "half an hour is " << halfhour.count() << " hours\n"; }
Output:
one day is 24 hours half an hour is 0.5 hours
[edit] See also
| constructs new duration (public member function of std::chrono::duration) | 


